1850 Belgian general election explained

Election Name:1850 Belgian general election
Country:Belgium
Type:parliamentary
Previous Election:1848 Belgian general election
Previous Year:1848
Next Election:1852 Belgian general election
Next Year:1852
Seats For Election:54 of the 108 seats in the Chamber of Representatives
Majority Seats:55
Leader1:Charles Rogier
Leader Since1:Candidate for PM
Party1:Liberal Party (Belgium)
Seats Before1:83 seats
Seats1:32
Seats After1:69
Seat Change1: 14
Popular Vote1:15,320
Percentage1:54.80%
Party2:Catholic
Seats Before2:25 seats
Seats2:22
Seats After2:39
Seat Change2: 14
Popular Vote2:11,618
Percentage2:41.56%
Color2:FFFF00
Government
Posttitle:Government after election
Before Election:Rogier I
Before Party:Liberal Party (Belgium)
After Election:Rogier I
After Party:Liberal Party (Belgium)

Partial general elections were held in Belgium on 11 June 1850.[1] [2] In the Chamber of Representatives elections the result was a victory for the Liberal Party, who won 69 of the 108 seats.[2] Voter turnout was 69.1%, although only 40,435 people were eligible to vote.

Under the alternating system, elections were only held in five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.

Results

Chamber of Representatives

Notes and References

  1. Codebook Constituency-level Elections Archive, 2003
  2. Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105