1848 United States presidential election in Iowa explained

See main article: 1848 United States presidential election.

Election Name:1848 United States presidential election in Iowa
Country:Iowa
Type:presidential
Ongoing:no
Next Election:1852 United States presidential election in Iowa
Next Year:1852
Election Date:November 7, 1848
Image1:Lewis Cass circa 1855.jpg
Nominee1:Lewis Cass
Party1:Democratic Party (United States)
Home State1:Michigan
Running Mate1:William O. Butler
Electoral Vote1:4
Popular Vote1:11,238
Percentage1:50.46%
Nominee2:Zachary Taylor
Party2:Whig Party (United States)
Home State2:Louisiana
Running Mate2:Millard Fillmore
Electoral Vote2:0
Popular Vote2:9,930
Percentage2:44.59%
Map Size:x200px
President
Before Election:James K. Polk
Before Party:Democratic Party (United States)
After Election:Zachary Taylor
After Party:Whig Party (United States)

The 1848 United States presidential election in Iowa took place on November 7, 1848, as part of the 1848 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Iowa voted for the Democratic candidate Lewis Cass in the state's first presidential election, over Whig candidate Zachary Taylor and Free Soil candidate Martin Van Buren. Cass won Iowa by a margin of 5.87%.

This is one of just three times (the others being 1988 and 2000) that a losing Democrat carried Iowa. Taylor became the first of currently only six American presidents to have never won Iowa since its statehood.

The 1848 election in Iowa began a trend in which the state would vote the same as neighboring Wisconsin, as the two states have voted in lockstep with each other on all but 6 occasions - 1892, 1924, 1940, 1976, 2004, and 2020.

See also