1848 United States presidential election in Indiana explained

See main article: 1848 United States presidential election.

Election Name:1848 United States presidential election in Indiana
Country:Indiana
Type:presidential
Ongoing:no
Previous Election:1844 United States presidential election in Indiana
Previous Year:1844
Next Election:1852 United States presidential election in Indiana
Next Year:1852
Election Date:November 7, 1848
Image1:Lewis Cass circa 1855.jpg
Nominee1:Lewis Cass
Party1:Democratic Party (United States)
Home State1:Michigan
Running Mate1:William O. Butler
Electoral Vote1:12
Popular Vote1:74,745
Percentage1:48.93%
Nominee2:Zachary Taylor
Party2:Whig Party (United States)
Home State2:Louisiana
Running Mate2:Millard Fillmore
Electoral Vote2:0
Popular Vote2:69,907
Percentage2:45.77%
Image3:Portrait of Martin Van Buren (cropped).jpg
Nominee3:Martin Van Buren
Party3:Free Soil Party
Home State3:New York
Running Mate3:Charles F. Adams
Electoral Vote3:0
Popular Vote3:8,100
Percentage3:5.30%
Map Size:300px
President
Before Election:James K. Polk
Before Party:Democratic Party (United States)
Before Color:FF3333
After Election:Zachary Taylor
After Party:Whig Party (United States)
After Color:FF3333

The 1848 United States presidential election in Indiana took place on November 7, 1848, as part of the 1848 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana voted for the Democratic candidate, Lewis Cass, over Whig candidate Zachary Taylor and Free Soil candidate Martin Van Buren. Cass won Indiana by a narrow margin of 3.16%.

This is one of just two times (the other being the extremely disputed and very narrow election of 1876) that a losing Democratic candidate carried Indiana, and the only time that a Democrat who lost the national popular vote carried the state.

See also