1848 United States presidential election in Illinois explained

See main article: 1848 United States presidential election.

Election Name:1848 United States presidential election in Illinois
Country:Illinois
Flag Year:1818
Type:presidential
Ongoing:no
Previous Election:1844 United States presidential election in Illinois
Previous Year:1844
Next Election:1852 United States presidential election in Illinois
Next Year:1852
Election Date:November 7, 1848
Image1:Lewis Cass circa 1855.jpg
Nominee1:Lewis Cass
Party1:Democratic Party (United States)
Home State1:Michigan
Running Mate1:William O. Butler
Electoral Vote1:9
Popular Vote1:55,952
Percentage1:44.91%
Nominee2:Zachary Taylor
Party2:Whig Party (United States)
Home State2:Louisiana
Running Mate2:Millard Fillmore
Electoral Vote2:0
Popular Vote2:52,853
Percentage2:42.42%
Image3:Portrait of Martin Van Buren (cropped).jpg
Nominee3:Martin Van Buren
Party3:Free Soil Party
Home State3:New York
Running Mate3:Charles F. Adams
Electoral Vote3:0
Popular Vote3:15,702
Percentage3:12.60%
Map Size:200px
President
Before Election:James K. Polk
Before Party:Democratic Party (United States)
After Election:Zachary Taylor
After Party:Whig Party (United States)

The 1848 United States presidential election in Illinois took place on November 7, 1848, as part of the 1848 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

Illinois narrowly voted for the Democratic candidate, Lewis Cass, over Whig candidate Zachary Taylor and Free Soil candidate Martin Van Buren. Cass won Illinois by a tight margin of 2.49%. This was the last time until 2000 that Illinois would back a losing Democrat in a presidential election and the last time until 2004 that they would back a Democrat that lost the popular vote.

See also