1846 Maine gubernatorial election explained

Election Name:1846 Maine gubernatorial election
Country:Maine
Type:Presidential
Ongoing:no
Previous Election:1845 Maine gubernatorial election
Previous Year:1845
Next Election:1847 Maine gubernatorial election
Next Year:1847
Election Date:14 September 1846
Nominee1:John W. Dana
Party1:Democratic Party (United States)
Popular Vote1:36,031
Percentage1:47.62%
Nominee2:David Bronson
Party2:Whig Party (United States)
Popular Vote2:29,557
Percentage2:39.06%
Nominee3:Samuel Fessenden
Party3:Liberty Party (United States, 1840)
Popular Vote3:9,398
Percentage3:12.42%
Governor
Before Election:Hugh J. Anderson
Before Party:Democratic Party (United States)
After Election:John W. Dana
After Party:Democratic Party (United States)

The 1846 Maine gubernatorial election was held on September 14, 1846, in order to elect the Governor of Maine. Former acting governor and Democratic nominee John W. Dana defeated Whig nominee and former member of theMaine Senate David Bronson and Liberty Party candidate and former member of the Massachusetts State Senate Samuel Fessenden. However, as no candidate received a majority of the total votes cast as was required by Maine law, the election was forwarded to the Maine legislature, who chose Dana as governor.[1]

General election

On election day, September 14, 1846, former Democratic acting governor John W. Dana won the election by a margin of 6,474 votes against his foremost opponent Whig nominee David Bronson, thereby retaining Democratic control over the office of governor. Dana was sworn in as the 21st governor of Maine on 12 May 1847.[2]

Results

Notes and References

  1. Web site: Gov. John Winchester Dana . nga.org . 16 April 2024.
  2. Web site: ME Governor . ourcampaigns.com . 21 April 2005 . 16 April 2024.