| Election Name: | 1846 Indiana gubernatorial election |
| Country: | Indiana |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1843 Indiana gubernatorial election |
| Previous Year: | 1843 |
| Next Election: | 1849 Indiana gubernatorial election |
| Next Year: | 1849 |
| Election Date: | August 3, 1846 |
| Nominee1: | James Whitcomb |
| Party1: | Democratic Party (United States) |
| Popular Vote1: | 64,104 |
| Percentage1: | 50.65% |
| Nominee2: | Joseph G. Marshall |
| Party2: | Whig Party (United States) |
| Popular Vote2: | 60,138 |
| Percentage2: | 47.52% |
| Map Size: | 250px |
| Governor | |
| Before Election: | James Whitcomb |
| Before Party: | Democratic Party (United States) |
| After Election: | James Whitcomb |
| After Party: | Democratic Party (United States) |
The 1846 Indiana gubernatorial election was held on August 3, 1846.[1]
Incumbent Democratic Governor James Whitcomb defeated Whig nominee Joseph G. Marshall and Liberty nominee Stephen C. Stevens with 50.65% of the vote.