1845 Virginia gubernatorial election explained
Election Name: | 1845 Virginia gubernatorial election |
Country: | Virginia |
Type: | Presidential |
Ongoing: | no |
Previous Election: | 1842 Virginia gubernatorial election |
Previous Year: | 1842 |
Next Election: | 1848 Virginia gubernatorial election |
Next Year: | 1848 |
Election Date: | 10 December 1845 |
Image1: | Hon. Smith - NARA - 528722.jpg |
Nominee1: | William Smith |
Party1: | Democratic Party (United States) |
1Data1: | 94 (58.75%) |
Nominee2: | John Brockenbrough |
1Data2: | 40 (25.00%) |
Image3: | 3x4.svg |
Nominee3: | Valentine W. Southall |
1Data3: | 11 (6.88%) |
Governor |
Before Election: | James McDowell |
Before Party: | Democratic Party (United States) |
After Election: | William Smith |
After Party: | Democratic Party (United States) |
The 1845 Virginia gubernatorial election was held on 10 December 1845 in order to elect the Governor of Virginia. Democratic nominee and former U.S. House representative William Smith defeated John Brockenbrough and 15 other candidates.
General election
On 10 December 1845, the Virginian General Assembly began voting for governor. William Smith, who had previously been selected by a caucus to be Democratic nominee,[1] was nominated alongside John Brockenbrough and 14 other candidates. Smith won a majority of the votes and was sworn in as governor on 1 January 1846.[2] [3]
Results
Notes and References
- News: Harper . Kenton . 18 December 1845 . Virginia Legislature . Staunton Spectator And General Advertiser . 2.
- News: Barber . J. H. . 20 December 1845 . State Elections . Newport Mercury . 3.
- Book: Virginia General Assembly . 1845 . Journal of the House of Delegates of the Commonwealth of Virginia . Superintendent Public Printing. .