| Election Name: | 1845 Vermont gubernatorial election |
| Country: | Vermont |
| Flag Year: | 1837 |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1844 Vermont gubernatorial election |
| Previous Year: | 1844 |
| Next Election: | 1846 Vermont gubernatorial election |
| Next Year: | 1846 |
| Election Date: | September 2, 1845 |
| Nominee1: | William Slade |
| Party1: | Whig Party (United States) |
| Electoral Vote1: | 132 |
| Popular Vote1: | 22,770 |
| Percentage1: | 47.18% |
| Nominee2: | Daniel Kellogg |
| Party2: | Democratic Party (United States) |
| Electoral Vote2: | 75 |
| Popular Vote2: | 18,594 |
| Percentage2: | 38.53% |
| Nominee3: | William R. Shafter |
| Party3: | Liberty Party (United States, 1840) |
| Electoral Vote3: | 14 |
| Popular Vote3: | 6,534 |
| Percentage3: | 13.54% |
| Map Size: | 220px |
| Governor | |
| Before Election: | William Slade |
| Before Party: | Whig Party (United States) |
| After Election: | William Slade |
| After Party: | Whig Party (United States) |
The 1845 Vermont gubernatorial election was held on September 2, 1845.[1]
Incumbent Whig Governor William Slade defeated Democratic nominee Daniel Kellogg and Liberty nominee William R. Shafter.
Since no candidate received a majority in the popular vote, Slade was elected by the Vermont General Assembly per the state constitution.
As no candidate received a majority of the vote, the Vermont General Assembly was required to decide the election, both Houses meeting jointly choosing among the top three vote-getters, Slade, Kellogg, and Shafter. The legislative election was held on October 9, 1845.[4] [5] [6]