1845 New Hampshire gubernatorial election explained

Election Name:1845 New Hampshire gubernatorial election
Country:New Hampshire
Type:Presidential
Ongoing:no
Previous Election:1844 New Hampshire gubernatorial election
Previous Year:1844
Next Election:1846 New Hampshire gubernatorial election
Next Year:1846
Election Date:11 March 1845
Nominee1:John Hardy Steele
Party1:Democratic Party (United States)
Popular Vote1:23,406
Percentage1:51.14%
Nominee2:Anthony Colby
Party2:Whig Party (United States)
Popular Vote2:15,585
Percentage2:34.05%
Nominee3:Daniel Hoit
Party3:Liberty Party (United States, 1840)
Popular Vote3:5,786
Percentage3:12.64%
Map Size:245px
Governor
Before Election:John Hardy Steele
Before Party:Democratic Party (United States)
After Election:John Hardy Steele
After Party:Democratic Party (United States)

The 1845 New Hampshire gubernatorial election was held on 11 March 1845 in order to elect the Governor of New Hampshire. Incumbent Democratic Governor John Hardy Steele won re-election against Whig nominee and former member of the New Hampshire House of Representatives Anthony Colby and Liberty nominee Daniel Hoit in a rematch of the previous election.[1]

General election

On election day, 11 March 1845, incumbent Democratic Governor John Hardy Steele won re-election by a margin of 7,821 votes against his foremost opponent Whig nominee Anthony Colby, thereby retaining Democratic control over the office of Governor. Steele was sworn in for his second term on 4 June 1845.[2]

Results

Notes and References

  1. Web site: John Hardy Steele . 2 April 2024 . National Governors Association.
  2. Web site: NH Governor . ourcampaigns.com . 3 June 2005 . 2 April 2024.