See main article: 1844 United States presidential election.
Election Name: | 1844 United States presidential election in Vermont |
Country: | Vermont |
Flag Year: | 1837 |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1840 United States presidential election in Vermont |
Previous Year: | 1840 |
Next Election: | 1848 United States presidential election in Vermont |
Next Year: | 1848 |
Election Date: | November 1 - December 4, 1844 |
Image1: | Clay 1848.jpg |
Nominee1: | Henry Clay |
Party1: | Whig Party (United States) |
Home State1: | Kentucky |
Running Mate1: | Theodore Frelinghuysen |
Electoral Vote1: | 6 |
Popular Vote1: | 26,780 |
Percentage1: | 54.84% |
Nominee2: | James K. Polk |
Party2: | Democratic Party (United States) |
Home State2: | Tennessee |
Running Mate2: | George M. Dallas |
Electoral Vote2: | 0 |
Popular Vote2: | 18,049 |
Percentage2: | 36.96% |
Image3: | James Birney(Cropped).jpg |
Nominee3: | James G. Birney |
Party3: | Liberty Party (United States, 1840) |
Home State3: | Michigan |
Running Mate3: | Thomas Morris |
Electoral Vote3: | 0 |
Popular Vote3: | 3,970 |
Percentage3: | 8.13% |
Map Size: | 301px |
President | |
Before Election: | John Tyler |
Before Party: | Independent (politician) |
After Election: | James K. Polk |
After Party: | Democratic Party (United States) |
The 1844 United States presidential election in Vermont took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.
Vermont voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk and Liberty candidate James G. Birney. Clay won Vermont by a margin of 17.88%.
With 54.84% of the popular vote, Vermont would prove to be Henry Clay's second strongest state after Rhode Island. Vermont would also prove to be James G. Birney's third strongest state after New Hampshire and Massachusetts.[1]