1844 United States presidential election in Pennsylvania explained

See main article: 1844 United States presidential election.

Election Name:1844 United States presidential election in Pennsylvania
Country:Pennsylvania
Type:presidential
Ongoing:no
Previous Election:1840 United States presidential election in Pennsylvania
Previous Year:1840
Next Election:1848 United States presidential election in Pennsylvania
Next Year:1848
Election Date:November 1 – December 4, 1844
Image1:Polk 1849.jpg
Nominee1:James K. Polk
Party1:Democratic Party (United States)
Home State1:Tennessee
Running Mate1:George M. Dallas
Electoral Vote1:26
Popular Vote1:167,447
Percentage1:50.50%
Nominee2:Henry Clay
Party2:Whig Party (United States)
Home State2:Kentucky
Running Mate2:Theodore Frelinghuysen
Electoral Vote2:0
Popular Vote2:161,125
Percentage2:48.59%
President
Before Election:John Tyler
Before Party:Independent (politician)
After Election:James K. Polk
After Party:Democratic Party (United States)

The 1844 United States presidential election in Pennsylvania took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Democratic candidate, James K. Polk, over the Whig candidate, Henry Clay. Polk won Pennsylvania by a narrow margin of 1.91%.

Results

1844 United States presidential election in Pennsylvania[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticJames K. Polk167,44750.50%26
WhigHenry Clay161,12548.59%0
LibertyJames G. Birney3,0000.90%0
Totals331,572100.0%26

See also

Notes and References

  1. Web site: 1844 Presidential General Election Results - Pennsylvania. U.S. Election Atlas. 4 August 2012.