1844 United States presidential election in North Carolina explained

See main article: 1844 United States presidential election.

Election Name:1844 United States presidential election in North Carolina
Country:North Carolina
Type:presidential
Ongoing:no
Previous Election:1840 United States presidential election in North Carolina
Previous Year:1840
Next Election:1848 United States presidential election in North Carolina
Next Year:1848
Election Date:November 1 - December 4, 1844
Image1:Clay 1848.jpg
Nominee1:Henry Clay
Party1:Whig Party (United States)
Home State1:Kentucky
Running Mate1:Theodore Frelinghuysen
Electoral Vote1:11
Popular Vote1:43,232
Percentage1:52.39%
Nominee2:James K. Polk
Party2:Democratic Party (United States)
Home State2:Tennessee
Running Mate2:George M. Dallas
Electoral Vote2:0
Popular Vote2:39,287
Percentage2:47.60%
President
Before Election:John Tyler
Before Party:Independent (politician)
After Election:James K. Polk
After Party:Democratic Party (United States)

The 1844 United States presidential election in North Carolina took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.

North Carolina voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won North Carolina by a margin of 4.63%.

With 52.39% of the popular vote, North Carolina would be Henry Clay's fourth-strongest state after Rhode Island, Vermont and Kentucky.[1] This was also the last presidential election until 1992 when a Democrat would win without carrying the state of North Carolina. James K. Polk is one of two presidents to lose his birth state in a successful presidential bid. The other is Donald Trump of New York.

Notes and References

  1. Web site: 1844 Presidential Election Statistics. Dave Leip’s Atlas of U.S. Presidential Elections. 2018-03-05.