1844 United States presidential election in New York explained

See main article: 1844 United States presidential election.

Election Name:1844 United States presidential election in New York
Country:New York
Flag Year:1778
Type:presidential
Ongoing:no
Previous Election:1840 United States presidential election in New York
Previous Year:1840
Next Election:1848 United States presidential election in New York
Next Year:1848
Turnout:92.1%[1] 0.2 pp
Election Date:November 1 – December 4, 1844
Image1:Polk 1849.jpg
Nominee1:James K. Polk
Party1:Democratic Party (United States)
Home State1:Tennessee
Running Mate1:George M. Dallas
Electoral Vote1:36
Popular Vote1:237,588
Percentage1:48.90%
Nominee2:Henry Clay
Party2:Whig Party (United States)
Home State2:Kentucky
Running Mate2:Theodore Frelinghuysen
Electoral Vote2:0
Popular Vote2:232,482
Percentage2:47.85%
President
Before Election:John Tyler
Before Party:Independent (politician)
After Election:James K. Polk
After Party:Democratic Party (United States)

The 1844 United States presidential election in New York took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 36 representatives, or electors to the Electoral College, who voted for President and Vice President.

New York voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won New York by a narrow margin of 1.05%. New York was decisive; if Clay had won the state, he would have received 141 electoral votes, more than the 138 needed to win at the time. Fulton and Cayuga would not vote Democratic again until 1964.

See also

Notes and References

  1. Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.