1844 United States presidential election in Michigan explained

See main article: 1844 United States presidential election.

Election Name:1844 United States presidential election in Michigan
Country:Michigan
Type:presidential
Ongoing:no
Previous Election:1840 United States presidential election in Michigan
Previous Year:1840
Next Election:1848 United States presidential election in Michigan
Next Year:1848
Election Date:November 1 - December 4, 1844
Image1:Polk 1849.jpg
Nominee1:James K. Polk
Party1:Democratic Party (United States)
Home State1:Tennessee
Running Mate1:George M. Dallas
Electoral Vote1:5
Popular Vote1:27,737
Percentage1:49.75%
Nominee2:Henry Clay
Party2:Whig Party (United States)
Home State2:Kentucky
Running Mate2:Theodore Frelinghuysen
Electoral Vote2:0
Popular Vote2:24,375
Percentage2:43.72%
Image3:James Birney(Cropped).jpg
Nominee3:James G. Birney
Party3:Liberty Party (United States, 1840)
Home State3:Michigan
Running Mate3:Thomas Morris
Electoral Vote3:0
Popular Vote3:3,639
Percentage3:6.53%
President
Before Election:John Tyler
Before Party:Independent (politician)
After Election:James K. Polk
After Party:Democratic Party (United States)
Map Size:300px

The 1844 United States presidential election in Michigan took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Michigan voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay and Liberty candidate James G. Birney. Polk won Michigan by a margin of 6.03%.

With 6.53% of the popular vote, Michigan would prove to be Jame G. Birney's fourth strongest state after New Hampshire, Massachusetts and Vermont.[1]

See also

Notes and References

  1. Web site: 1844 Presidential Election Statistics. Dave Leip’s Atlas of U.S. Presidential Elections. 2018-03-05.