See main article: 1844 United States presidential election.
| Election Name: | 1844 United States presidential election in Kentucky |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1840 United States presidential election in Kentucky |
| Previous Year: | 1840 |
| Next Election: | 1848 United States presidential election in Kentucky |
| Next Year: | 1848 |
| Election Date: | November 1 - December 4, 1844 |
| Image1: | Clay 1848.jpg |
| Nominee1: | Henry Clay |
| Party1: | Whig Party (United States) |
| Home State1: | Kentucky |
| Running Mate1: | Theodore Frelinghuysen |
| Electoral Vote1: | 12 |
| Popular Vote1: | 61,249 |
| Percentage1: | 54.09% |
| Nominee2: | James K. Polk |
| Party2: | Democratic Party (United States) |
| Home State2: | Tennessee |
| Running Mate2: | George M. Dallas |
| Electoral Vote2: | 0 |
| Popular Vote2: | 51,988 |
| Percentage2: | 45.91% |
| Map Size: | 380px |
| President | |
| Before Election: | John Tyler |
| Before Party: | Independent (politician) |
| After Election: | James K. Polk |
| After Party: | Democratic Party (United States) |
The 1844 United States presidential election in Kentucky took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.
Kentucky voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won his home state by a margin of 8.18%.
With 54.09% of the popular vote, Clay's home state would be his third strongest victory after Rhode Island and Vermont.[1]