| Election Name: | 1844 New Hampshire gubernatorial election |
| Country: | New Hampshire |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1843 New Hampshire gubernatorial election |
| Previous Year: | 1843 |
| Next Election: | 1845 New Hampshire gubernatorial election |
| Next Year: | 1845 |
| Election Date: | 12 March 1844 |
| Nominee1: | John Hardy Steele |
| Party1: | Democratic Party (United States) |
| Popular Vote1: | 25,986 |
| Percentage1: | 53.37% |
| Nominee2: | Anthony Colby |
| Party2: | Whig Party (United States) |
| Popular Vote2: | 14,750 |
| Percentage2: | 30.29% |
| Nominee3: | Daniel Hoit |
| Party3: | Liberty Party (United States, 1840) |
| Popular Vote3: | 5,767 |
| Percentage3: | 11.84% |
| Map Size: | 245px |
| Governor | |
| Before Election: | Henry Hubbard |
| Before Party: | Democratic Party (United States) |
| After Election: | John Hardy Steele |
| After Party: | Democratic Party (United States) |
The 1844 New Hampshire gubernatorial election was held on 12 March 1844 in order to elect the Governor of New Hampshire. Democratic nominee and former member of the New Hampshire House of Representatives John Hardy Steele defeated Whig nominee and former member of the New Hampshire House of Representatives Anthony Colby, Conservative nominee John H. White and Liberty nominee Daniel Hoit.[1]
On election day, 12 March 1844, Democratic nominee John Hardy Steele won the election by a margin of 11,236 votes against his foremost opponent Whig nominee Anthony Colby, thereby retaining Democratic control over the office of Governor. Steele was sworn in as the 19th Governor of New Hampshire on 6 June 1844.[2]