1843 New Hampshire gubernatorial election explained

Election Name:1843 New Hampshire gubernatorial election
Country:New Hampshire
Type:Presidential
Ongoing:no
Previous Election:1842 New Hampshire gubernatorial election
Previous Year:1842
Next Election:1844 New Hampshire gubernatorial election
Next Year:1844
Election Date:14 March 1843
Nominee1:Henry Hubbard
Party1:Democratic Party (United States)
Popular Vote1:23,050
Percentage1:51.58%
Nominee2:Anthony Colby
Party2:Whig Party (United States)
Popular Vote2:12,553
Percentage2:28.09%
Nominee4:John H. White
Party4:Conservative Party (United States)
Popular Vote4:5,597
Percentage4:12.53%
Nominee5:Daniel Hoit
Party5:Liberty Party (United States, 1840)
Popular Vote5:3,392
Percentage5:7.59%
Map Size:245px
Governor
Before Election:Henry Hubbard
Before Party:Democratic Party (United States)
After Election:Henry Hubbard
After Party:Democratic Party (United States)

The 1843 New Hampshire gubernatorial election was held on 14 March 1843 in order to elect the Governor of New Hampshire. Incumbent Democratic Governor Henry Hubbard won re-election against Whig nominee and former member of the New Hampshire House of Representatives Anthony Colby, Conservative nominee John H. White and Liberty nominee Daniel Hoit.[1]

General election

On election day, 14 March 1843, Democratic Governor Henry Hubbard won re-election by a margin of 10,497 votes against his foremost opponent Whig nominee Anthony Colby, thereby retaining Democratic control over the office of Governor. Hubbard was sworn in for his second term on 6 June 1843.[2]

Results

Notes and References

  1. Web site: Henry Hubbard . 2 April 2024 . National Governors Association.
  2. Web site: NH Governor . ourcampaigns.com . 3 June 2005 . 2 April 2024.