1843 Maine gubernatorial election explained

Election Name:1843 Maine gubernatorial election
Country:Maine
Type:Presidential
Ongoing:no
Previous Election:1842 Maine gubernatorial election
Previous Year:1842
Next Election:1844 Maine gubernatorial election
Next Year:1844
Election Date:11 September 1843
Nominee1:Hugh J. Anderson
Party1:Democratic Party (United States)
Popular Vote1:32,034
Percentage1:50.25%
Nominee2:Edward Robinson
Party2:Whig Party (United States)
Popular Vote2:20,975
Percentage2:32.90%
Nominee4:James Appleton
Party4:Liberty Party (United States, 1840)
Popular Vote4:6,746
Percentage4:10.58%
Nominee5:Edward Kavanagh
Party5:Independent Democrat
Popular Vote5:3,221
Percentage5:5.05%
Governor
Before Election:John W. Dana (Acting)
Before Party:Democratic Party (United States)
After Election:Hugh J. Anderson
After Party:Democratic Party (United States)

The 1843 Maine gubernatorial election was held on 11 September 1843 in order to elect the Governor of Maine. Democratic nominee and former member of the U.S. House of Representatives from Maine's 6th district Hugh J. Anderson defeated Whig nominee and former U.S. Representative from Maine's 3rd congressional district Edward Robinson, Liberty Party candidate and former member of the Maine House of Representatives James Appleton and incumbent Independent Democratic Governor Edward Kavanagh.[1]

General election

On election day, 11 September 1843, Democratic nominee Hugh J. Anderson won the election by a margin of 11,059 votes against his foremost opponent Whig nominee Edward Robinson, thereby retaining Democratic control over the office of governor. Anderson was sworn in as the 20th Governor of Maine on 5 January 1844.[2]

Results

Notes and References

  1. Web site: Gov. Hugh Johnston Anderson . nga.org . 16 April 2024.
  2. Web site: ME Governor . ourcampaigns.com . 22 April 2005 . 16 April 2024.