See main article: 1840 United States presidential election.
| Election Name: | 1840 United States presidential election in Virginia |
| Country: | Virginia |
| Flag Year: | 1788 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1836 United States presidential election in Virginia |
| Previous Year: | 1836 |
| Next Election: | 1844 United States presidential election in Virginia |
| Next Year: | 1844 |
| Election Date: | October 30 – December 2, 1840 |
| Image1: | Martin Van Buren circa 1837 crop.jpg |
| Nominee1: | Martin Van Buren |
| Party1: | Democratic Party (United States) |
| Home State1: | New York |
| Running Mate1: | Richard M. Johnson |
| Electoral Vote1: | 23 |
| Popular Vote1: | 43,757 |
| Percentage1: | 50.65% |
| Nominee2: | William Henry Harrison |
| Party2: | Whig Party (United States) |
| Home State2: | Ohio |
| Running Mate2: | John Tyler |
| Electoral Vote2: | 0 |
| Popular Vote2: | 42,637 |
| Percentage2: | 49.35% |
| Map Size: | 360px |
| President | |
| Before Election: | Martin Van Buren |
| Before Party: | Democratic Party (United States) |
| After Election: | William Henry Harrison |
| After Party: | Whig Party (United States) |
The 1840 United States presidential election in Virginia took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.
Virginia voted for the Democratic candidate, incumbent President Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren narrowly won Virginia by a margin of 1.3%, or 1,120 votes.
| 1840 United States presidential election in Virginia[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren (inc.) | 43,757 | 50.65% | 23 | |
| Whig | William Henry Harrison | 42,637 | 49.35% | 0 | |
| Totals | 86,394 | 100.0% | 23 | ||