See main article: 1840 United States presidential election.
| Election Name: | 1840 United States presidential election in Mississippi |
| Country: | Mississippi |
| Flag Year: | 1837 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1836 United States presidential election in Mississippi |
| Previous Year: | 1836 |
| Next Election: | 1844 United States presidential election in Mississippi |
| Next Year: | 1844 |
| Election Date: | October 30 - December 2, 1840 |
| Image1: | William Henry Harrison crop.jpg |
| Nominee1: | William Henry Harrison |
| Party1: | Whig Party (United States) |
| Home State1: | Ohio |
| Running Mate1: | John Tyler |
| Electoral Vote1: | 4 |
| Popular Vote1: | 19,515 |
| Percentage1: | 53.43% |
| Nominee2: | Martin Van Buren |
| Party2: | Democratic Party (United States) |
| Home State2: | New York |
| Running Mate2: | none |
| Electoral Vote2: | 0 |
| Popular Vote2: | 17,010 |
| Percentage2: | 46.57% |
| President | |
| Before Election: | Martin Van Buren |
| Before Party: | Democratic Party (United States) |
| After Election: | William Henry Harrison |
| After Party: | Whig Party (United States) |
| Map Size: | 205px |
The 1840 United States presidential election in Mississippi took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Mississippi voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Mississippi by a margin of 6.86%. As of 2020, this is the only presidential election in American history in which Mississippi has voted for a different candidate than Alabama.