See main article: 1840 United States presidential election.
| Election Name: | 1840 United States presidential election in Maine |
| Country: | Maine |
| Flag Image: | Flag of the United States (1837–1845).svg |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1836 United States presidential election in Maine |
| Previous Year: | 1836 |
| Next Election: | 1844 United States presidential election in Maine |
| Next Year: | 1844 |
| Election Date: | October 30 - December 2, 1840 |
| Image1: | William Henry Harrison crop.jpg |
| Nominee1: | William Henry Harrison |
| Party1: | Whig Party (United States) |
| Home State1: | Ohio |
| Running Mate1: | John Tyler |
| Electoral Vote1: | 10 |
| Popular Vote1: | 46,612 |
| Percentage1: | 50.23% |
| Nominee2: | Martin Van Buren |
| Party2: | Democratic Party (United States) |
| Home State2: | New York |
| Running Mate2: | none |
| Electoral Vote2: | 0 |
| Popular Vote2: | 46,190 |
| Percentage2: | 49.77% |
| Map Size: | 225px |
| President | |
| Before Election: | Martin Van Buren |
| Before Party: | Democratic Party (United States) |
| Before Color: | FF3333 |
| After Election: | William Henry Harrison |
| After Party: | Whig Party (United States) |
| After Color: | FF3333 |
The 1840 United States presidential election in Maine took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for president and vice president.
Maine voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won the state by a very narrow margin of 0.46%.
Maine was typically a Democratic state during the Second Party System, however, with Harrison narrowly winning the state, this would be the only time that a Whig presidential candidate would win Maine.