1840 United States presidential election in Connecticut explained

See main article: 1840 United States presidential election.

Election Name:1840 United States presidential election in Connecticut
Country:Connecticut
Type:presidential
Ongoing:no
Previous Election:1836 United States presidential election in Connecticut
Previous Year:1836
Next Election:1844 United States presidential election in Connecticut
Next Year:1844
Election Date:October 30 - December 2, 1840
Image1:William Henry Harrison crop.jpg
Nominee1:William Henry Harrison
Party1:Whig Party (United States)
Home State1:Ohio
Running Mate1:John Tyler
Electoral Vote1:8
Popular Vote1:31,598
Percentage1:55.55%
Nominee2:Martin Van Buren
Party2:Democratic Party (United States)
Home State2:New York
Running Mate2:none
Electoral Vote2:0
Popular Vote2:25,281
Percentage2:44.45%
Map Size:250px
President
Before Election:Martin Van Buren
Before Party:Democratic Party (United States)
Before Color:FF3333
After Election:William Henry Harrison
After Party:Whig Party (United States)
After Color:FF3333

The 1840 United States presidential election in Connecticut took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

Connecticut voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Connecticut by a margin of 11.1%.

See also