| Election Name: | 1840 Indiana gubernatorial election |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1837 Indiana gubernatorial election |
| Previous Year: | 1837 |
| Next Election: | 1843 Indiana gubernatorial election |
| Next Year: | 1843 |
| Election Date: | 3 August 1840 |
| Nominee1: | Samuel Bigger |
| Party1: | Whig Party (United States) |
| Popular Vote1: | 62,932 |
| Percentage1: | 53.69% |
| Nominee2: | Tilghman Howard |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 54,274 |
| Percentage2: | 46.31% |
| Governor | |
| Before Election: | David Wallace |
| Before Party: | Whig Party (United States) |
| After Election: | Samuel Bigger |
| After Party: | Whig Party (United States) |
The 1840 Indiana gubernatorial election was held on 3 August 1840 in order to elect the Governor of Indiana. Whig nominee and former member of the Indiana House of Representatives Samuel Bigger defeated Democratic nominee and incumbent member of the U.S. House of Representatives from Indiana's 7th district Tilghman Howard.[1]
On election day, 3 August 1840, Whig nominee Samuel Bigger won the election by a margin of 8,658 votes against his opponent Democratic nominee Tilghman Howard, thereby retaining Whig control over the office of Governor. Bigger was sworn in as the 7th Governor of Indiana on 9 December 1840.[2]