| Election Name: | 1838 Rhode Island gubernatorial election |
| Country: | Rhode Island |
| Flag Year: | 1836 |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1837 Rhode Island gubernatorial election |
| Previous Year: | 1837 |
| Next Election: | 1839 Rhode Island gubernatorial election |
| Next Year: | 1839 |
| Election Date: | April 18, 1838 |
| Nominee1: | William Sprague |
| Party1: | Whig Party (United States) |
| Popular Vote1: | 3,984 |
| Percentage1: | 52.51% |
| Nominee2: | John Brown Francis |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 3,504 |
| Percentage2: | 46.18% |
| Map Size: | 200px |
| Governor | |
| Before Election: | John Brown Francis |
| Before Party: | Democratic Party (United States) |
| After Election: | William Sprague |
| After Party: | Whig Party (United States) |
The 1838 Rhode Island gubernatorial election was held on April 18, 1838.[1] [2]
Incumbent Democratic Governor John Brown Francis ran for election to a sixth term but was defeated by Whig nominee William Sprague.