See main article: 1836 United States presidential election.
Election Name: | 1836 United States presidential election in Vermont |
Country: | Vermont |
Flag Year: | 1804 |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1832 United States presidential election in Vermont |
Previous Year: | 1832 |
Next Election: | 1840 United States presidential election in Vermont |
Next Year: | 1840 |
Election Date: | November 3 - December 7, 1836 |
Image1: | William Henry Harrison by James Reid Lambdin, 1835 crop.jpg |
Nominee1: | William Henry Harrison |
Party1: | Whig Party (United States) |
Home State1: | Ohio |
Running Mate1: | Francis Granger |
Electoral Vote1: | 7 |
Popular Vote1: | 20,994 |
Percentage1: | 59.93% |
Nominee2: | Martin Van Buren |
Party2: | Democratic Party (United States) |
Home State2: | New York |
Running Mate2: | Richard Mentor Johnson |
Electoral Vote2: | 0 |
Popular Vote2: | 14,037 |
Percentage2: | 40.07% |
Map Size: | 260px |
President | |
Before Election: | Andrew Jackson |
Before Party: | Democratic Party (United States) |
Before Color: | FF3333 |
After Election: | Martin Van Buren |
After Party: | Democratic Party (United States) |
After Color: | FF3333 |
The 1836 United States presidential election in Vermont took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
Vermont voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Vermont by a margin of 19.86%.
This would be the final time a Democratic candidate would carry Essex County until Franklin D. Roosevelt won it 104 years later in 1940.
1836 would stand as the strongest performance for a Democratic candidate in Vermont until 96 years later in 1932, when Franklin D. Roosevelt performed slightly better with 41.08%.
Harrison would later win Vermont again four years later when he successfully defeated Van Buren.