1836 United States presidential election in New Hampshire explained

See main article: 1836 United States presidential election.

Election Name:1836 United States presidential election in New Hampshire
Country:New Hampshire
Type:presidential
Ongoing:no
Previous Election:1832 United States presidential election in New Hampshire
Previous Year:1832
Next Election:1840 United States presidential election in New Hampshire
Next Year:1840
Election Date:November 3 - December 7, 1836
Image1:Martin Van Buren circa 1837 crop.jpg
Nominee1:Martin Van Buren
Party1:Democratic Party (United States)
Home State1:New York
Running Mate1:Richard Mentor Johnson
Electoral Vote1:7
Popular Vote1:18,697
Percentage1:75.01%
Nominee2:William Henry Harrison
Party2:Whig Party (United States)
Home State2:Ohio
Running Mate2:Francis Granger
Electoral Vote2:0
Popular Vote2:6,228
Percentage2:24.99%
President
Before Election:Andrew Jackson
Before Party:Democratic Party (United States)
Before Color:FF3333
After Election:Martin Van Buren
After Party:Democratic Party (United States)
After Color:FF3333

The 1836 United States presidential election in New Hampshire took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 50.02%. As of 2020, this remains the strongest ever performance by any presidential candidate in New Hampshire since the creation of the modern Democratic party in 1828.

See also