See main article: 1836 United States presidential election.
| Election Name: | 1836 United States presidential election in Missouri |
| Country: | Missouri |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1832 United States presidential election in Missouri |
| Previous Year: | 1832 |
| Next Election: | 1840 United States presidential election in Missouri |
| Next Year: | 1840 |
| Election Date: | November 3 – December 7, 1836 |
| Image1: | Martin Van Buren circa 1837 crop.jpg |
| Nominee1: | Martin Van Buren |
| Party1: | Democratic Party (United States) |
| Home State1: | New York |
| Running Mate1: | Richard Johnson |
| Electoral Vote1: | 4 |
| Popular Vote1: | 10,995 |
| Percentage1: | 59.98% |
| Nominee2: | Hugh White |
| Party2: | Whig Party (United States) |
| Home State2: | Tennessee |
| Running Mate2: | John Tyler |
| Electoral Vote2: | 0 |
| Popular Vote2: | 7,337 |
| Percentage2: | 40.02% |
| Colour2: | 800080 |
The 1836 United States presidential election in Missouri took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Missouri by a margin of 19.96%.
| 1836 United States presidential election in Missouri[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 10,995 | 59.98% | 4 | |
| Whig | Hugh White | 7,337 | 40.02% | 0 | |
| Totals | 18,332 | 100.0% | 4 | ||