1836 United States presidential election in Mississippi explained

See main article: 1836 United States presidential election.

Election Name:1836 United States presidential election in Mississippi
Country:Mississippi
Flag Year:1836
Type:presidential
Ongoing:no
Previous Election:1832 United States presidential election in Mississippi
Previous Year:1832
Next Election:1840 United States presidential election in Mississippi
Next Year:1840
Election Date:November 3 – December 7, 1836
Image1:Martin Van Buren circa 1837 crop.jpg
Nominee1:Martin Van Buren
Party1:Democratic Party (United States)
Home State1:New York
Running Mate1:Richard Johnson
Electoral Vote1:4
Popular Vote1:10,297
Percentage1:51.28%
Nominee2:Hugh White
Party2:Whig Party (United States)
Home State2:Tennessee
Running Mate2:John Tyler
Electoral Vote2:0
Popular Vote2:9,782
Percentage2:48.72%
Map Size:200px
Colour2:800080

The 1836 United States presidential election in Mississippi took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Mississippi voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Mississippi by a margin of 2.56%.

Results

United States presidential election in Mississippi, 1836[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticMartin Van Buren10,29751.28%4
WhigHugh White9,78248.72%0
Totals20,079100.00%4

Notes and References

  1. Web site: 1836 Presidential General Election Results - Mississippi. U.S. Election Atlas. 15 April 2013.