See main article: 1836 United States presidential election.
Election Name: | 1836 United States presidential election in Massachusetts |
Country: | Massachusetts |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1832 United States presidential election in Massachusetts |
Previous Year: | 1832 |
Next Election: | 1840 United States presidential election in Massachusetts |
Next Year: | 1840 |
Turnout: | 43.4%[1] 4.0 pp |
Election Date: | November 3 – December 7, 1836 |
Image1: | Black Dan (cropped).jpg |
Nominee1: | Daniel Webster |
Party1: | Whig Party (United States) |
Home State1: | Massachusetts |
Running Mate1: | Francis Granger |
Electoral Vote1: | 14 |
Popular Vote1: | 41,201 |
Percentage1: | 55.13% |
Nominee2: | Martin Van Buren |
Party2: | Democratic Party (United States) |
Home State2: | New York |
Running Mate2: | Richard Johnson |
Electoral Vote2: | 0 |
Popular Vote2: | 33,486 |
Percentage2: | 44.81% |
Map Size: | 300px |
Colour1: | F88379 |
The 1836 United States presidential election in Massachusetts took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.
Massachusetts voted for Whig candidate and state native Daniel Webster over the Democratic candidate, Martin Van Buren. Webster won Massachusetts by a margin of 10.32%.
In a unique strategy to throw the election into the house of representatives, the Whigs ran four different candidates in different sections of the United States. This is the only state in which Daniel Webster was on the ballot.[2]
1836 United States presidential election in Massachusetts[3] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Whig | Daniel Webster | 41,201 | 55.13% | 14 | |
Democratic | Martin Van Buren | 33,486 | 44.81% | 0 | |
N/A | Other | 45 | 0.06% | 0 | |
Totals | 74,732 | 100.00% | 14 | ||