1836 United States presidential election in Maine explained

Election Name:	1836 United States presidential election in Maine
Country:	Maine
Flag Image:	Flag of the United States (1836–1837).svg
Type:	presidential
Ongoing:	no
Previous Election:	1832 United States presidential election in Maine
Previous Year:	1832
Next Election:	1840 United States presidential election in Maine
Next Year:	1840
Election Date:	November 3 – December 7, 1836
Image1:	Martin Van Buren circa 1837 crop.jpg
Nominee1:	Martin Van Buren
Party1:	Democratic Party (United States)
Home State1:	New York
Running Mate1:	Richard Johnson
Electoral Vote1:	10
Popular Vote1:	22,825
Percentage1:	58.92%
Nominee2:	William Henry Harrison
Party2:	Whig Party (United States)
Home State2:	Ohio
Running Mate2:	Francis Granger
Electoral Vote2:	0
Popular Vote2:	14,803
Percentage2:	38.21%
President
Before Election:	Andrew Jackson
Before Party:	Democratic Party (United States)
After Election:	Martin Van Buren
After Party:	Democratic Party (United States)

The 1836 United States presidential election in Maine took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President.

Maine voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won the state by a margin of 20.71%.

Van Buren would be the final Democratic presidential candidate until Lyndon B. Johnson in 1964 to carry Somerset County.

Results

1836 United States presidential election in Maine^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren	22,825	58.92%	10
	Whig	William Henry Harrison	14,803	38.21%	0
	N/A	Other	1,112	2.87%	0
Totals			38,740	100.0%	10