See main article: 1836 United States presidential election.
| Election Name: | 1836 United States presidential election in Connecticut |
| Country: | Connecticut |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1832 United States presidential election in Connecticut |
| Previous Year: | 1832 |
| Next Election: | 1840 United States presidential election in Connecticut |
| Next Year: | 1840 |
| Election Date: | November 3 – December 7, 1836 |
| Image1: | Martin Van Buren circa 1837 crop.jpg |
| Nominee1: | Martin Van Buren |
| Party1: | Democratic Party (United States) |
| Home State1: | New York |
| Running Mate1: | Richard Johnson |
| Electoral Vote1: | 8 |
| Popular Vote1: | 19,294 |
| Percentage1: | 50.65% |
| Nominee2: | William Henry Harrison |
| Party2: | Whig Party (United States) |
| Home State2: | Ohio |
| Running Mate2: | Francis Granger |
| Electoral Vote2: | 0 |
| Popular Vote2: | 18,799 |
| Percentage2: | 49.35% |
| Map Size: | 250px |
The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a narrow margin of 1.3%.
As a result of his win, Van Buren also became the first Democratic presidential candidate to carry Connecticut.
| 1836 United States presidential election in Connecticut[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 19,294 | 50.65% | 8 | |
| Whig | William Henry Harrison | 18,799 | 49.35% | 0 | |
| Totals | 38,093 | 100.0% | 8 | ||