| Election Name: | 1836 South Carolina gubernatorial election |
| Country: | South Carolina |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1834 South Carolina gubernatorial election |
| Previous Year: | 1834 |
| Next Election: | 1838 South Carolina gubernatorial election |
| Next Year: | 1838 |
| Election Date: | 10 December 1836 |
| Nominee1: | Pierce Mason Butler |
| Party1: | Democratic Party (United States) |
| Popular Vote1: | 1 |
| Percentage1: | 100.00% |
| Governor | |
| Before Election: | George McDuffie |
| Before Party: | Democratic Party (United States) |
| After Election: | Pierce Mason Butler |
| After Party: | Democratic Party (United States) |
The 1836 South Carolina gubernatorial election was held on 10 December 1836 in order to elect the Governor of South Carolina. Democratic candidate Pierce Mason Butler was elected by the South Carolina General Assembly as he ran unopposed. The exact number of votes cast in this election is unknown.[1]
On election day, 10 December 1836, Democratic candidate Pierce Mason Butler was elected by the South Carolina General Assembly, thereby retaining Democratic control over the office of Governor. Butler was sworn in as the 56th Governor of South Carolina on 17 January 1837.[2]