1836 Rhode Island gubernatorial election explained

Election Name:1836 Rhode Island gubernatorial election
Country:Rhode Island
Flag Year:1822
Type:Presidential
Ongoing:no
Previous Election:1835 Rhode Island gubernatorial election
Previous Year:1835
Next Election:1837 Rhode Island gubernatorial election
Next Year:1837
Election Date:April 20, 1836
Nominee1:John Brown Francis
Party1:Democratic Party (United States)
Popular Vote1:4,020
Percentage1:56.22%
Nominee2:Tristam Burges
Party2:Whig Party (United States)
Popular Vote2:2,984
Percentage2:41.73%
Map Size:200px
Governor
Before Election:John Brown Francis
Before Party:Democratic Party (United States)
After Election:John Brown Francis
After Party:Democratic Party (United States)

The 1836 Rhode Island gubernatorial election was held on April 20, 1836.[1]

Incumbent Democratic Governor John Brown Francis won re-election to a fourth term, defeating Whig nominee Tristam Burges and Constitutional Party candidate Charles Collins.

General election

Candidates

Results

Notes and References

  1. News: . March 23, 1836 . Shall Tristram Burges . The Rhode-Island Republican . Newport, R.I. . 2 . 19 October 2021 .
  2. Web site: The Constitutional Party in Rhode Island, 1834-1837 . DeSimone . Russell . March 6, 2021 . Small State Big History . 19 October 2021 .
  3. News: . February 3, 1836 . The Constitutional Party . The Rhode-Island Republican . Newport, R.I. . 2 . 19 October 2021 .
  4. News: . March 9, 1836 . Constitutional Nomination . The Rhode-Island Republican . Newport, R.I. . 2 . 19 October 2021 .