| Election Name: | 1836 New Hampshire gubernatorial election |
| Country: | New Hampshire |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1835 New Hampshire gubernatorial election |
| Previous Year: | 1835 |
| Next Election: | 1837 New Hampshire gubernatorial election |
| Next Year: | 1837 |
| Election Date: | 8 March 1836 |
| Nominee1: | Isaac Hill |
| Party1: | Democratic Party (United States) |
| Popular Vote1: | 24,904 |
| Percentage1: | 81.22% |
| Nominee2: | Joseph Healey |
| Party2: | Whig Party (United States) |
| Popular Vote2: | 2,566 |
| Percentage2: | 8.37% |
| Nominee3: | George Sullivan |
| Popular Vote3: | 2,230 |
| Percentage3: | 7.27% |
| Governor | |
| Before Election: | William Badger |
| Before Party: | Democratic Party (United States) |
| After Election: | Isaac Hill |
| After Party: | Democratic Party (United States) |
The 1836 New Hampshire gubernatorial election was held on 8 March 1836 in order to elect the Governor of New Hampshire. Former Democratic United States Senator from New Hampshire Isaac Hill defeated Whig nominee Joseph Healey and former Federalist Attorney General of New Hampshire George Sullivan.[1]
On election day, 8 March 1836, Democratic nominee Isaac Hill won the election by a margin of 22,338 votes against his foremost opponent Whig nominee Joseph Healey, thereby retaining Democratic control over the office of Governor. Hill was sworn in as the 16th Governor of New Hampshire on 2 June 1836.[2]