| Election Name: | 1834 Vermont gubernatorial election |
| Country: | Vermont |
| Flag Year: | 1804 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1833 Vermont gubernatorial election |
| Previous Year: | 1833 |
| Next Election: | 1835 Vermont gubernatorial election |
| Next Year: | 1835 |
| Nominee1: | William A. Palmer |
| Party1: | Anti-Masonic Party |
| Popular Vote1: | 17,131 |
| Percentage1: | 45.4% |
| Electoral Vote1: | 147 |
| Nominee2: | William Czar Bradley |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 10,365 |
| Percentage2: | 27.5% |
| Electoral Vote2: | 13 |
| Nominee3: | Horatio Seymour |
| Party3: | Whig Party (United States) |
| Popular Vote3: | 10,159 |
| Percentage3: | 26.9% |
| Electoral Vote3: | 2 |
| Governor | |
| Before Election: | William A. Palmer |
| Before Party: | Anti-Masonic Party |
| After Election: | William A. Palmer |
| After Party: | Anti-Masonic Party |
The 1834 Vermont gubernatorial election took place in September and October, and resulted in the reelection of William A. Palmer to a one-year term as governor.[1]
The candidates for governor in the general election held on September 2, 1834 were: incumbent William A. Palmer (Anti-Masonic); William Czar Bradley (Democratic); and Horatio Seymour (Whig).[1] In the general election, the General Assembly, which met in Montpelier on October 9, determined that the results were: total votes, 37,759; Palmer, 17,131 (45.4%); Bradley, 10,365 (27.5%); Seymour, 10,159 (26.9%); scattering, 84 (0.2%).[1]
Because no candidate received the popular vote majority required by the Constitution of Vermont, the Vermont General Assembly was required to choose.[2] In the assembly contest, Palmer won on the first ballot. With 168 votes cast, 85 were necessary for choice.[2] The reported totals were: Palmer, 147; Bradley 13; William A. Griswold, 3; Samuel C. Crafts, 1; Daniel Pierce Thompson, 1; Seymour, 2; John Roberts, 1.[2]
In the race for lieutenant governor, the total votes were 37,579.[1] Anti-Mason and incumbent Lebbeus Egerton received 17,069 votes (45.4%). Democrat Truman Chittenden received 10,408 (27.7%). Whig Samuel Clark received 9,978 (26.6%). 124 (0.3%) were recorded as scattering.[1]
In the vote by the Vermont General Assembly, Egerton was elected with 114 votes.[2] Clark received 69 and Chittenden 28. Robert Pierpoint received 1 vote, Jedediah Harris received 1, and Edwin Egerton received 1.[2]
There were 37,458 votes cast for state treasurer.[1] Anti-Mason and incumbent Augustine Clarke received 17,063 (45.6%).[1] Democrat Charles R. Cleaves received 10,337 (27.6%), and Whig John Spaulding received 9,903 (26.4%).[1] 155 (0.4%) votes were recorded as scattering.[1]
In the general assembly contest, Clarke won with 111 votes.[2] Spaulding received 76 votes, Cleaves received 19, and Thomas D. Hammond received 1.[2]