| Election Name: | 1833 Rhode Island gubernatorial election |
| Country: | Rhode Island |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1832 Rhode Island gubernatorial election |
| Previous Year: | 1832 |
| Next Election: | 1834 Rhode Island gubernatorial election |
| Next Year: | 1834 |
| Election Date: | 3 April 1833 |
| Nominee1: | John Brown Francis |
| Party1: | Democratic Party (United States) |
| Popular Vote1: | 4,025 |
| Percentage1: | 54.98% |
| Nominee2: | Lemuel H. Arnold |
| Party2: | National Republican Party (United States) |
| Popular Vote2: | 3,292 |
| Percentage2: | 44.97% |
| Map Size: | 200px |
| Governor | |
| Before Election: | Lemuel H. Arnold |
| Before Party: | National Republican Party (United States) |
| After Election: | John Brown Francis |
| After Party: | Democratic Party (United States) |
The 1833 Rhode Island gubernatorial election was held on 3 April 1833 in order to elect the Governor of Rhode Island. Democratic nominee and former member of the Rhode Island Senate John Brown Francis defeated incumbent National Republican Governor Lemuel H. Arnold.[1]
On election day, 3 April 1833, Democratic nominee John Brown Francis won the election by a margin of 733 votes against his opponent incumbent National Republican Governor Lemuel H. Arnold, thereby gaining Democratic control over the office of Governor. Francis was sworn in as the 13th Governor of Rhode Island on 1 May 1833.[2]