See main article: 1832 United States presidential election.
| Election Name: | 1832 United States presidential election in Rhode Island |
| Country: | Rhode Island |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1828 United States presidential election in Rhode Island |
| Previous Year: | 1828 |
| Next Election: | 1836 United States presidential election in Rhode Island |
| Next Year: | 1836 |
| Election Date: | November 2 – December 5, 1832 |
| Image1: | Henry Clay (copy after Edward Dalton Marchant).jpg |
| Nominee1: | Henry Clay |
| Party1: | National Republican Party (United States) |
| Home State1: | Kentucky |
| Running Mate1: | John Sergeant |
| Electoral Vote1: | 4 |
| Popular Vote1: | 2,810 |
| Percentage1: | 56.93% |
| Nominee2: | Andrew Jackson |
| Party2: | Democratic Party (United States) |
| Home State2: | Tennessee |
| Running Mate2: | Martin Van Buren |
| Electoral Vote2: | 0 |
| Popular Vote2: | 2,126 |
| Percentage2: | 43.07% |
| Map Size: | 250px |
The 1832 United States presidential election in Rhode Island took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Rhode Island voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Rhode Island by a margin of 13.86%.
| 1832 United States presidential election in Rhode Island[1] | ||||||
|---|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | ||
| width: 3px" | National Republican | Henry Clay | 2,810 | 56.93% | 4 | |
| Democratic | Andrew Jackson (incumbent) | 2,126 | 43.07% | 0 | ||
| Totals | 4,936 | 100.0% | 4 | |||