1832 United States presidential election in North Carolina explained

See main article: 1832 United States presidential election.

Election Name:1832 United States presidential election in North Carolina
Country:North Carolina
Type:presidential
Ongoing:no
Previous Election:1828 United States presidential election in North Carolina
Previous Year:1828
Next Election:1836 United States presidential election in North Carolina
Next Year:1836
Election Date:November 2 – December 5, 1832
Image1:Andrew jackson head.jpg
Nominee1:Andrew Jackson
Party1:Democratic Party (United States)
Home State1:Tennessee
Running Mate1:Martin Van Buren
Electoral Vote1:15
Popular Vote1:25,261
Percentage1:84.77%
Nominee2:Henry Clay
Party2:National Republican Party (United States)
Home State2:Kentucky
Running Mate2:John Sergeant
Electoral Vote2:0
Popular Vote2:4,538
Percentage2:15.23%

The 1832 United States presidential election in North Carolina took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

North Carolina voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won North Carolina by a margin of 69.54 points., this is the last occasion when Wilkes County voted for a Democratic presidential candidate.[1]

Results

1832 United States presidential election in North Carolina[2]
PartyCandidateVotesPercentageElectoral votes
DemocraticAndrew Jackson (incumbent)25,26184.77%15
width: 3px" National RepublicanHenry Clay4,53815.23%0
Totals29,799100.0%15

Notes and References

  1. Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 265-271
  2. Web site: 1832 Presidential General Election Results – North Carolina. U.S. Election Atlas. 12 April 2013.