1832 United States presidential election in New Hampshire explained

See main article: 1832 United States presidential election.

Election Name:1832 United States presidential election in New Hampshire
Country:New Hampshire
Type:presidential
Ongoing:no
Previous Election:1828 United States presidential election in New Hampshire
Previous Year:1828
Next Election:1836 United States presidential election in New Hampshire
Next Year:1836
Election Date:November 2 – December 5, 1832
Image1:Andrew jackson head.jpg
Nominee1:Andrew Jackson
Party1:Democratic Party (United States)
Home State1:Tennessee
Running Mate1:Martin Van Buren
Electoral Vote1:7
Popular Vote1:24,855
Percentage1:56.76%
Nominee2:Henry Clay
Party2:National Republican Party (United States)
Home State2:Kentucky
Running Mate2:John Sergeant
Electoral Vote2:0
Popular Vote2:18,938
Percentage2:43.24%

The 1832 United States presidential election in New Hampshire took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won New Hampshire by a margin of 13.52%.

Results

1832 United States presidential election in New Hampshire[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticAndrew Jackson (incumbent)24,85556.76%7
width: 3px" National RepublicanHenry Clay18,93843.24%0
Totals43,793100.0%7

See also

Notes and References

  1. Web site: 1832 Presidential General Election Results - New Hampshire. U.S. Election Atlas. 12 April 2013.