1832 United States presidential election in Missouri explained

See main article: 1832 United States presidential election.

Election Name:1832 United States presidential election in Missouri
Country:Missouri
Type:presidential
Ongoing:no
Previous Election:1828 United States presidential election in Missouri
Previous Year:1828
Next Election:1836 United States presidential election in Missouri
Next Year:1836
Election Date:November 2 – December 5, 1832
Image1:Andrew jackson head.jpg
Nominee1:Andrew Jackson
Party1:Democratic Party (United States)
Home State1:Tennessee
Running Mate1:Martin Van Buren
Electoral Vote1:4
Popular Vote1:5,192
Percentage1:100.00%

The 1832 United States presidential election in Missouri took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Missouri voted unanimously for the Democratic Party candidate, Andrew Jackson. This is the last time any party swept every county in the state.

Results

1832 United States presidential election in Missouri[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticAndrew Jackson (incumbent)5,192100.00%4
Totals5,192100.0%4

See also

Notes and References

  1. Web site: 1832 Presidential General Election Results - Missouri. U.S. Election Atlas. 12 April 2013.