See main article: 1832 United States presidential election.
| Election Name: | 1832 United States presidential election in Indiana |
| Country: | Indiana |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1828 United States presidential election in Indiana |
| Previous Year: | 1828 |
| Next Election: | 1836 United States presidential election in Indiana |
| Next Year: | 1836 |
| Election Date: | November 2 – December 5, 1832 |
| Image1: | Andrew jackson head.jpg |
| Nominee1: | Andrew Jackson |
| Party1: | Democratic Party (United States) |
| Home State1: | Tennessee |
| Running Mate1: | Martin Van Buren |
| Electoral Vote1: | 9 |
| Popular Vote1: | 31,551 |
| Percentage1: | 67.10% |
| Nominee2: | Henry Clay |
| Party2: | National Republican Party (United States) |
| Home State2: | Kentucky |
| Running Mate2: | John Sergeant |
| Electoral Vote2: | 0 |
| Popular Vote2: | 15,472 |
| Percentage2: | 32.90% |
The 1832 United States presidential election in Indiana took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
Indiana voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Indiana by a margin of 34.20%.
As of 2020, this remains the strongest performance by a Democrat in Indiana.[1]
| 1832 United States presidential election in Indiana[2] | ||||||
|---|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | ||
| Democratic | Andrew Jackson (incumbent) | 31,551 | 67.10% | 9 | ||
| width: 3px" | National Republican | Henry Clay | 15,472 | 32.90% | 0 | |
| Totals | 47,023 | 100.0% | 9 | |||