1832 United States presidential election in Illinois explained

See main article: 1832 United States presidential election.

Election Name:1832 United States presidential election in Illinois
Country:Illinois
Type:presidential
Ongoing:no
Previous Election:1828 United States presidential election in Illinois
Previous Year:1828
Next Election:1836 United States presidential election in Illinois
Next Year:1836
Election Date:November 2 – December 5, 1832
Image1:Andrew jackson head.jpg
Nominee1:Andrew Jackson
Party1:Democratic Party (United States)
Home State1:Tennessee
Running Mate1:Martin Van Buren
Electoral Vote1:5
Popular Vote1:14,609
Percentage1:68.01%
Nominee2:Henry Clay
Party2:National Republican Party (United States)
Home State2:Kentucky
Running Mate2:John Sergeant
Electoral Vote2:0
Popular Vote2:6,745
Percentage2:31.40%

The 1832 United States presidential election in Illinois took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Illinois voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay, and the Anti-Masonic Party candidate, William Wirt. Jackson won Illinois by a margin of 36.61%. This is the most recent election in which Edwards County voted for the Democratic candidate.

As of 2020, this remains the strongest performance by a Democrat in Illinois.[1]

Results

1832 United States presidential election in Illinois[2]
PartyCandidateVotesPercentageElectoral votes
DemocraticAndrew Jackson (incumbent)14,60968.01%5
width: 3px" National RepublicanHenry Clay6,74531.40%0
Anti-MasonicWilliam Wirt970.45%0
N/AOthers300.14%0
Totals21,481100.0%5

See also

Notes and References

  1. Web site: Dave Leip's Atlas of U.S. Presidential Elections . 2023-01-10 . uselectionatlas.org.
  2. Web site: 1832 Presidential General Election Results - Illinois. U.S. Election Atlas. 12 April 2013.