See main article: 1832 United States presidential election.
| Election Name: | 1832 United States presidential election in Alabama |
| Country: | Alabama |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1828 United States presidential election in Alabama |
| Previous Year: | 1828 |
| Next Election: | 1836 United States presidential election in Alabama |
| Next Year: | 1836 |
| Election Date: | November 2 – December 5, 1832 |
| Image1: | Andrew jackson head.jpg |
| Nominee1: | Andrew Jackson |
| Party1: | Democratic Party (United States) |
| Home State1: | Tennessee |
| Running Mate1: | Martin Van Buren |
| Electoral Vote1: | 7 |
| Popular Vote1: | 14,286 |
| Percentage1: | 99.97% |
| President | |
| Before Election: | John Quincy Adams |
| Before Party: | Democratic-Republican Party |
| After Election: | Andrew Jackson |
| After Party: | Democratic Party (United States) |
The 1832 United States presidential election in Alabama took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose seven representatives, or electors, to the Electoral College, who voted for president and vice president.
Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Alabama by a margin of 99.94%.
| 1832 United States presidential election in Alabama[1] | ||||||
|---|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | ||
| Democratic | Andrew Jackson (incumbent) | 14,286 | 99.97% | 7 | ||
| width: 3px" | National Republican | Henry Clay | 5 | 0.03% | 0 | |
| Totals | 14,291 | 100.00% | 7 | |||