1828 United States presidential election in Pennsylvania explained

See main article: 1828 United States presidential election.

Election Name:1828 United States presidential election in Pennsylvania
Country:Pennsylvania
Type:presidential
Ongoing:no
Previous Election:1824 United States presidential election in Pennsylvania
Previous Year:1824
Next Election:1832 United States presidential election in Pennsylvania
Next Year:1832
Election Date:October 31 – December 2, 1828
Image1:Andrew Jackson.jpg
Nominee1:Andrew Jackson
Party1:Democratic Party (United States)
Home State1:Tennessee
Running Mate1:John C. Calhoun
Electoral Vote1:28
Popular Vote1:101,652
Percentage1:66.66%
Nominee2:John Quincy Adams
Party2:National Republican Party (United States)
Home State2:Massachusetts
Running Mate2:Richard Rush
Electoral Vote2:0
Popular Vote2:50,848
Percentage2:33.34%
President
Before Election:John Quincy Adams
Before Party:Democratic-Republican Party
After Election:Andrew Jackson
After Party:Democratic Party (United States)

The 1828 United States presidential election in Pennsylvania took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 28 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Pennsylvania by a margin of 33.32%.

To date, this is still the best Democratic Party performance in Pennsylvania in any federal election. It was also the last time to date Union County, Pennsylvania voted Democratic.

Results

1828 United States presidential election in Pennsylvania[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticAndrew Jackson101,65266.66%28
National RepublicanJohn Quincy Adams (incumbent)50,84833.34%0
Totals152,500100.0%28

Notes and References

  1. Web site: 1828 Presidential General Election Results - Pennsylvania. U.S. Election Atlas. 4 August 2012.