See main article: 1828 United States presidential election.
Election Name: | 1828 United States presidential election in Ohio |
Country: | Ohio |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1824 United States presidential election in Ohio |
Previous Year: | 1824 |
Next Election: | 1832 United States presidential election in Ohio |
Next Year: | 1832 |
Election Date: | October 31 – December 2, 1828 |
Image1: | Andrew Jackson.jpg |
Nominee1: | Andrew Jackson |
Party1: | Democratic Party (United States) |
Home State1: | Tennessee |
Running Mate1: | John C. Calhoun |
Electoral Vote1: | 16 |
Popular Vote1: | 67,595 |
Percentage1: | 51.60% |
Nominee2: | John Quincy Adams |
Party2: | National Republican Party (United States) |
Home State2: | Massachusetts |
Running Mate2: | Richard Rush |
Electoral Vote2: | 0 |
Popular Vote2: | 63,394 |
Percentage2: | 48.40% |
Map Size: | 200px |
President | |
Before Election: | John Quincy Adams |
Before Party: | Democratic-Republican |
After Election: | Andrew Jackson |
After Party: | Democratic Party (United States) |
The 1828 United States presidential election in Ohio took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for President and Vice President.
Ohio voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Ohio by a narrow margin of 3.2%. This was the first election of the Second Party System, and as such the first election in which Ohio voted for a candidate of a party other than the Democratic-Republicans.
1828 United States presidential election in Ohio[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 67,597 | 51.60% | 16 | |
National Republican | John Quincy Adams (incumbent) | 63,396 | 48.40% | 0 | |
Totals | 130,993 | 100.0% | 16 | ||