1828 United States presidential election in New Hampshire explained

See main article: 1828 United States presidential election.

Election Name:1828 United States presidential election in New Hampshire
Country:New Hampshire
Type:presidential
Ongoing:no
Previous Election:1824 United States presidential election in New Hampshire
Previous Year:1824
Next Election:1832 United States presidential election in New Hampshire
Next Year:1832
Election Date:October 31 – December 2, 1828
Image1:John Quincy Adams 1858 crop.jpg
Nominee1:John Quincy Adams
Party1:National Republican Party (United States)
Home State1:Massachusetts
Running Mate1:Richard Rush
Electoral Vote1:8
Popular Vote1:23,823
Percentage1:54.10%
Nominee2:Andrew Jackson
Party2:Democratic Party (United States)
Home State2:Tennessee
Running Mate2:John C. Calhoun
Electoral Vote2:0
Popular Vote2:20,212
Percentage2:45.90%

The 1828 United States presidential election in New Hampshire took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won New Hampshire by a margin of 8.2%.

Results

1828 United States presidential election in New Hampshire[1]
PartyCandidateVotesPercentageElectoral votes
National RepublicanJohn Quincy Adams (incumbent)23,82354.10%8
DemocraticAndrew Jackson20,21245.90%0
Totals44,035100.0%8

See also

Notes and References

  1. Web site: 1828 Presidential General Election Results - New Hampshire. U.S. Election Atlas. 28 February 2013.