See main article: 1828 United States presidential election.
| Election Name: | 1828 United States presidential election in Illinois |
| Country: | Illinois |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1824 United States presidential election in Illinois |
| Previous Year: | 1824 |
| Next Election: | 1832 United States presidential election in Illinois |
| Next Year: | 1832 |
| Election Date: | October 31 – December 2, 1828 |
| Image1: | Andrew Jackson.jpg |
| Nominee1: | Andrew Jackson |
| Party1: | Democratic Party (United States) |
| Home State1: | Tennessee |
| Running Mate1: | John C. Calhoun |
| Electoral Vote1: | 3 |
| Popular Vote1: | 9,560 |
| Percentage1: | 67.22% |
| Nominee2: | John Quincy Adams |
| Party2: | National Republican Party (United States) |
| Home State2: | Massachusetts |
| Running Mate2: | Richard Rush |
| Electoral Vote2: | 0 |
| Popular Vote2: | 4,662 |
| Percentage2: | 32.78% |
The 1828 United States presidential election in Illinois took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Illinois voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Illinois by a margin of 34.44%.
| 1828 United States presidential election in Illinois[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Andrew Jackson | 9,560 | 67.22% | 3 | |
| National Republican | John Quincy Adams (incumbent) | 4,662 | 32.78% | 0 | |
| Totals | 14,222 | 100.0% | 3 | ||