See main article: 1828 United States presidential election.
| Election Name: | 1828 United States presidential election in Connecticut |
| Country: | Connecticut |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1824 United States presidential election in Connecticut |
| Previous Year: | 1824 |
| Next Election: | 1832 United States presidential election in Connecticut |
| Next Year: | 1832 |
| Election Date: | October 31 – December 2, 1828 |
| Image1: | John Quincy Adams 1858 crop.jpg |
| Nominee1: | John Quincy Adams |
| Party1: | National Republican Party (United States) |
| Home State1: | Massachusetts |
| Running Mate1: | Richard Rush |
| Electoral Vote1: | 8 |
| Popular Vote1: | 13,829 |
| Percentage1: | 71.36% |
| Nominee2: | Andrew Jackson |
| Party2: | Democratic Party (United States) |
| Home State2: | Tennessee |
| Running Mate2: | John C. Calhoun |
| Electoral Vote2: | 0 |
| Popular Vote2: | 4,448 |
| Percentage2: | 22.95% |
| Map Size: | 250px |
The 1828 United States presidential election in Connecticut took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
Connecticut voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Connecticut by a margin of 48.41%.
With 71.36% of the popular vote, Connecticut would prove to be Adams' fourth strongest state in the 1828 election after Rhode Island, Massachusetts and Vermont.[1]
| 1828 United States presidential election in Connecticut[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| National Republican | John Quincy Adams (incumbent) | 13,829 | 71.36% | 8 | |
| Democratic | Andrew Jackson | 4,448 | 22.95% | 0 | |
| N/A | Other | 1,101 | 5.68% | 0 | |
| Totals | 19,378 | 100.0% | 8 | ||