1826 United States Senate election in Pennsylvania explained

The 1826 United States Senate election in Pennsylvania was held on December 12, 1826. Isaac D. Barnard was elected by the Pennsylvania General Assembly to the United States Senate.[1]

Results

The Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on December 12, 1826, to elect a Senator to serve the term beginning on March 4, 1827. Two ballots were recorded. The results of the second and final ballot of both houses combined are as follows:

|-|-bgcolor="#EEEEEE"| colspan="3" align="right" | Totals| align="right" | 133| align="right" | 100.00%|}

External links

Notes and References

  1. Web site: U.S. Senate Election - 12 December 1826. Wilkes University. 21 December 2012.