| Election Name: | 1826 Ohio gubernatorial election |
| Country: | Ohio |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1824 Ohio gubernatorial election |
| Previous Year: | 1824 |
| Next Election: | 1828 Ohio gubernatorial election |
| Next Year: | 1828 |
| Election Date: | 10 October 1826 |
| Nominee1: | Allen Trimble |
| Party1: | National Republican Party |
| Popular Vote1: | 71,475 |
| Percentage1: | 84.35% |
| Nominee2: | Alexander Campbell |
| Party2: | Democratic-Republican Party |
| Popular Vote2: | 4,765 |
| Percentage2: | 5.62% |
| Governor | |
| Before Election: | Jeremiah Morrow |
| Before Party: | Democratic-Republican Party |
| After Election: | Allen Trimble |
| After Party: | National Republican Party |
The 1826 Ohio gubernatorial election was held on 10 October 1826, in order to elect the Governor of Ohio. National Republican candidate and former Acting Governor Allen Trimble defeated Democratic-Republican candidates Alexander Campbell, Benjamin Tappan and John Bigger.[1]
On election day, 10 October 1826, National Republican candidate Allen Trimble won the election by a margin of 66,710 votes against his foremost opponent Democratic-Republican candidate Alexander Campbell, thereby gaining National Republican control over the office of Governor. Trimble was sworn in as the 10th Governor of Ohio on 19 December 1826.[2]